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[Question|问题咨询]: HCOMM_TA_CTP_UB_TIMEOUT 超时时间配置不太清楚用法 #685
kangfuanAdd on  Sep 4Closed at  Sep 8
kangfuan
Sep 4 Create

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问题描述

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既然档位有4个,那为什么又用[0-31]设置的值去除以8,根据结果来反推档位,再推时间。除法的结果是整除?带小数?带小数怎么跟档位挂钩呢,不觉得这个方法很绕吗?

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LLeewisCollaborators
Sep 4 associated Kanban: HCCL
LeewisCollaborators
Sep 4 Comments:

@frankang 感谢对于社区的关注与反馈;
当前HCOMM_TA_CTP_UB_TIMEOUT 超时时间是按照整除方式来计算,0-7 为0档,8-15为1档,16-23为2档,24-31为4档;分别对应相关时间;

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sqw
Sep 7 Comments:

预计解决时间2026/9/8

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Ssqw
Sep 7 Associated pull request
LeewisCollaborators
Sep 8 Comments:

感谢对于社区的关注与反馈,当前已针对文档中补充说明整除细节;相关上库PR:https://gitcode.com/cann/hccl/pull/2938

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LLeewisCollaborators
Sep 8 Assign sqw as responsible person
LLeewisCollaborators
Sep 8 changed custom category from 任务 to 文档
LLeewisCollaborators
Sep 8 changed custom category from 文档 to 咨询
LLeewisCollaborators
Sep 8 changed custom state from 进行中 to 已完成
LLeewisCollaborators
Sep 8 Close issue
CANN-robotCANN-robotCollaborators
Sep 8 Added label: resolved
LLeewisCollaborators
Sep 21 removed Kanban: HCCL