* https://leetcode.com/problems/merge-k-sorted-lists/
* Time O(N) | Space O(N)
* @param {ListNode[]} lists
* @return {ListNode}
*/
var mergeKLists = function (lists) {
let previous = null;
for (let i = 0; i < lists.length; i++) {
previous = mergeTwoLists(previous, lists[i]);
}
return previous;
};
var mergeTwoLists = function (list1, list2) {
let sentinel = (tail = new ListNode(0));
while (list1 && list2) {
const canAddL1 = list1.val <= list2.val;
if (canAddL1) {
tail.next = list1;
list1 = list1.next;
} else {
tail.next = list2;
list2 = list2.next;
}
tail = tail.next;
}
tail.next = list1 || list2;
return sentinel.next;
};
* https://leetcode.com/problems/merge-k-sorted-lists/
* Time O(N * log(K)) | Space O(N + K)
* @param {ListNode[]} lists
* @return {ListNode}
*/
var mergeKLists = function (lists) {
const minHeap = getMinHeap(lists);
return mergeLists(minHeap);
};
const getMinHeap = (lists) => {
const heap = new MinPriorityQueue({ priority: ({ val }) => val });
for (const node of lists) {
if (!node) continue;
heap.enqueue(node);
}
return heap;
};
const mergeLists = (minHeap) => {
let sentinel = (tail = new ListNode());
while (!minHeap.isEmpty()) {
const node = minHeap.dequeue().element;
tail.next = node;
tail = tail.next;
if (!node.next) continue;
minHeap.enqueue(node.next);
}
return sentinel.next;
};