* https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/
* Time O(N^2) | Space(H)
* @param {number[]} preorder
* @param {number[]} inorder
* @return {TreeNode}
*/
var buildTree = function (preorder, inorder) {
const isBaseCase = !preorder.length || !inorder.length;
if (isBaseCase) return null;
return dfs(preorder, inorder);
};
var dfs = (preorder, inorder) => {
const { leftInorder, mid, rightInorder } = getPointers(preorder, inorder);
const root = new TreeNode(inorder[mid]);
root.left = buildTree(preorder, leftInorder);
root.right = buildTree(preorder, rightInorder);
return root;
};
const getPointers = (preorder, inorder) => {
const next = preorder.shift();
const mid = inorder.indexOf(next);
const leftInorder = inorder.slice(0, mid);
const rightInorder = inorder.slice(mid + 1);
return { leftInorder, mid, rightInorder };
};
* https://leetcode.com/problems/construct-binary-tree-from-preorder-and-inorder-traversal/
* Time O(N) | Space(H)
* @param {number[]} preorder
* @param {number[]} inorder
* @return {TreeNode}
*/
var buildTree = function (
preorder,
inorder,
max = -Infinity,
indices = { preorder: 0, inorder: 0 },
) {
const isBaseCase = preorder.length <= indices.inorder;
if (isBaseCase) return null;
const isAtEnd = inorder[indices.inorder] === max;
if (isAtEnd) {
indices.inorder++;
return null;
}
return dfs(preorder, inorder, max, indices);
};
var dfs = (preorder, inorder, max, indices) => {
const val = preorder[indices.preorder++];
const root = new TreeNode(val);
root.left = buildTree(preorder, inorder, root.val, indices);
root.right = buildTree(preorder, inorder, max, indices);
return root;
};