* Greedy - Max
* Time O(N) | Space O(1)
* https://leetcode.com/problems/house-robber-ii/
* @param {number[]} nums
* @return {number}
*/
var rob = (nums) => {
const isBaseCase1 = nums.length === 0;
if (isBaseCase1) return 0;
const isBaseCase2 = nums.length === 1;
if (isBaseCase2) return nums[0];
const left = search(nums, 0, nums.length - 2);
const right = search(nums, 1, nums.length - 1);
return Math.max(left, right);
};
const search = (nums, start, end) => {
let [left, mid] = [0, 0];
for (let i = start; i <= end; i++) {
const temp = mid;
const right = nums[i];
const house = left + right;
mid = Math.max(mid, house);
left = temp;
}
return mid;
};