* Brute Force - Linear Search
* Time O(N^2) | Space O(1)
* https://leetcode.com/problems/contains-duplicate/
* @param {number[]} nums
* @return {boolean}
*/
var containsDuplicate = (nums) => {
for (let right = 0; right < nums.length; right++) {
for (let left = 0; left < right; left++) {
const isDuplicate = nums[left] === nums[right];
if (isDuplicate) return true;
}
}
return false;
};
* Sort - HeapSort Space O(1) | QuickSort Space O(log(N))
* Time O(N * log(N)) | Space O(1)
* https://leetcode.com/problems/contains-duplicate/
* @param {number[]} nums
* @return {boolean}
*/
var containsDuplicate = (nums) => {
nums.sort((a, b) => a - b);
return hasDuplicate(nums);
};
const hasDuplicate = (nums) => {
for (let curr = 0; curr < nums.length - 1; curr++) {
const next = curr + 1;
const isNextDuplicate = nums[curr] === nums[next];
if (isNextDuplicate) return true;
}
return false;
};
* Hash Set
* Time O(N) | Space O(N)
* https://leetcode.com/problems/contains-duplicate/
* @param {number[]} nums
* @return {boolean}
*/
var containsDuplicate = (nums) => {
const numsSet = new Set(nums);
const isEqual = numsSet.size === nums.length;
return !isEqual;
};
* Hash Set - Early Exit
* Time O(N) | Space O(N)
* https://leetcode.com/problems/contains-duplicate/
* @param {number[]} nums
* @return {boolean}
*/
var containsDuplicate = (nums, numsSet = new Set()) => {
for (const num of nums) {
if (numsSet.has(num)) return true;
numsSet.add(num);
}
return false;
};