* Brute Force - Linear Search
* Time O(N^2) | Space O(1)
* https://leetcode.com/problems/two-sum/
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = (nums, target) => {
for (let curr = 0; curr < nums.length; curr++) {
const complement = target - nums[curr];
for (let next = curr + 1; next < nums.length; next++) {
const num = nums[next];
const isTarget = num === complement;
if (isTarget) return [curr, next];
}
}
return [-1, -1];
};
* Hash Map - 2 Pass
* Time O(N) | Space O(N)
* https://leetcode.com/problems/two-sum/
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = (nums, target) => {
const map = getMap(nums);
return getSum(nums, target, map);
};
const getMap = (nums, map = new Map()) => {
for (let index = 0; index < nums.length; index++) {
map.set(nums[index], index);
}
return map;
};
const getSum = (nums, target, map) => {
for (let index = 0; index < nums.length; index++) {
const complement = target - nums[index];
const sumIndex = map.get(complement);
const isTarget = map.has(complement) && map.get(complement) !== index;
if (isTarget) return [index, sumIndex];
}
return [-1, -1];
};
* Hash Map - 1 Pass
* Time O(N) | Space O(N)
* https://leetcode.com/problems/two-sum/
* @param {number[]} nums
* @param {number} target
* @return {number[]}
*/
var twoSum = (nums, target, map = new Map()) => {
for (let index = 0; index < nums.length; index++) {
const num = nums[index];
const complement = target - num;
const sumIndex = map.get(complement);
const isTarget = map.has(complement);
if (isTarget) return [index, sumIndex];
map.set(num, index);
}
return [-1, -1];
};